Vector Distance Question

[Guest Red Ocktober]

how do i do this in BlitzMAX?

 

--Mike

[Aily]

distance betwen points

 

local v1:tvec3=vec3(1,2,3)
local v2:tvec3=vec3(4,5,6)

distance#=sqr( (v1.x-v2.x)^2 + (v1.y-v2.y)^2 + (v1.z-v2.z)^2 )

[Flexman]

Aily gives you the math which is better. If you're feeling lazy....

 

dist:float = Vec3(x1,y1,z1).DistanceTo(x2,y2,z2);

[Guest Red Ocktober]

THANKS... guys for both...

 

--Mike

[Naughty Alien]

..this one should be faster, in case many time in your loops is used..

 

local v1:tvec3=vec3(1,2,3)

local v2:tvec3=vec3(4,5,6)

 

distance!=sqr( ((v1.x-v2.x) * (v1.x-v2.x)) + ((v1.y-v2.y) * (v1.y-v2.y)) + ((v1.z-v2.z) * (v1.z-v2.z)) )

 

[Aily]

One my friend say me to compare squares, not distances, because SQR is heavy command. So

 

dist1#=(v1.x-v2.x) * (v1.x-v2.x) + (v1.y-v2.y) * (v1.y-v2.y) + (v1.z-v2.z) * (v1.z-v2.z)

dist2#=(v1.x-v3.x) * (v1.x-v3.x) + (v1.y-v3.y) * (v1.y-v3.y) + (v1.z-v3.z) * (v1.z-v3.z)

 

if dist1<dist2 ....

 

Without SQR calcilations

 

P.S. Cool glasses Alien